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Question

What will be the molarity of a solution, which contains 5.85 g of NaCl (s) per 500 mL?

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Solution

Calculating the number of moles of solute

Mass of solute (Nacl) = 5.85 g
Molar mass of solute (Nacl) = 58.5 g/mol

$∴$ Number of moles of solute (Nacl) =
$\frac{Mass of solute}{Molar mass of solute(Nacl)} = \frac{5.85}{58.5} = 0.1 m o l$

Molarity

To find molarity, formula used is:
Volume of the solution = 500 mL = 0.5 L

Molarity = $\frac{number of moles of solute}{Volume of solution (in L)}$

$= \frac{0.1 m o l}{0.5 L} = 0.2 m o l L^{- 1}$

Thus, molarity of the given solution is $0.2 m o l L^{- 1}$

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