What will be the molecular weight of $C a C l_{2}$ determined in its aq. solution experimentally from depression of freezing point?

111

No worries! We‘ve got your back. Try BYJU‘S free classes today!

<111

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

>111

No worries! We‘ve got your back. Try BYJU‘S free classes today!

data insufficient

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B <111
The vant Hoff factor (i) is $i = \frac{n (o b s e r v e d)}{n (t h e o r e t i c a l)} = \frac{(1 + 2)}{1} = 3$
The vant Hoff factor (i) is also given by the expresion $i = \frac{M (t h e o r e t i c a l)}{M (o b s e r v e d)}$
Hence, $\frac{(111)}{M (o b s e r v e d)} = 3$
$M (o b s e r v e d) = \frac{111}{3} < 111$

Suggest Corrections

Similar questions

Q. What will be the molecular weight of

N a C l

determined experimentally following elevation in the boiling point or depression in freezing point method?

If CaCl₂ were a non electrolyte the freezing point depression of a 0.1 m solution of CaCl₂in water would be 0.186 ^oC. What would be actual freezing point depression of this solution?

Q. The molecular weight of benzoic acid in benzene as determined by depression in freezing point method corresponds to:

Q. Assertion :The molecular weight of acetic acid determined by depression in freezing point method in benzene and water was found to be different. Reason: Water is polar and benzene is non-polar.

The molecular mass of benzoic acid in benzene, as determined by depression in freezing point method, corresponds to:

Join BYJU'S Learning Program

What will be the molecular weight of CaCl2 determined in its aq. solution experimentally from depression of freezing point?

The correct option is B <111The vant Hoff factor (i) is i=n(observed)n(theoretical)=(1+2)1=3The vant Hoff factor (i) is also given by the expresion i=M(theoretical)M(observed)Hence, (111)M(observed)=3M(observed)=1113<111

What will be the molecular weight of $C a C l_{2}$ determined in its aq. solution experimentally from depression of freezing point?