What will be the molecular weight of $N a C l$ determined experimentally following elevation in the boiling point or depression in freezing point method?

< 58.5

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> 58.5

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= 58.5

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None

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Solution

The correct option is B $< 58.5$
$N a C l \to N a^{+} + C l^{-}$
NaCl furnishes two ions on complete dissociation.
so i=2 and
Normal molecular weight of electrolyte >Experimental molecular weight.

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