Dear Student,
The answer by Sanskriti Srivastava was right but the the student didn't expressed it in terms of Kinetic energy.
K.E = 0.5 mv2 (1),
When the velocity of the body is doubled
K.E' = 0.5 m(2v)2 = 4 (0.5mv2) or
K.E' = 4K.E (2)
i.e., when the velocity of a body is doubled its kinetic energy increases by four times.
Regards