What will be the non-passing sight distance (in m) on highway for a design speed of 80 kmph when its ascending gradient is 3%? Assume brake efficiency as 50%, coefficient of friction as 0.7 and reaction time of 2.5 seconds.
121.91

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Solution

The correct option is A 121.91
$SSD = 0.278 V t + \frac{V^{2}}{254 (η_{b} f + S %)}$

$= 0.278 \times 80 \times 2.5 + \frac{80^{2}}{254 (0.5 \times 0.7 + 0.03)}$

$= 121.908 m$

$≃ 121.91 m$

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What will be the non-passing sight distance (in m) on highway for a design speed of 80 kmph when its ascending gradient is 3%? Assume brake efficiency as 50%, coefficient of friction as 0.7 and reaction time of 2.5 seconds.121.91

The correct option is A 121.91SSD=0.278Vt+V2254(ηbf+S%) =0.278×80×2.5+802254(0.5×0.7+0.03) =121.908m ≃121.91m

What will be the non-passing sight distance (in m) on highway for a design speed of 80 kmph when its ascending gradient is 3%? Assume brake efficiency as 50%, coefficient of friction as 0.7 and reaction time of 2.5 seconds.
121.91

The correct option is A 121.91
$SSD = 0.278 V t + \frac{V^{2}}{254 (η_{b} f + S %)}$

$= 0.278 \times 80 \times 2.5 + \frac{80^{2}}{254 (0.5 \times 0.7 + 0.03)}$

$= 121.908 m$

$≃ 121.91 m$