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Stopping Sight Distance

What will be ...

Question

What will be the non-passing sight distance on a highway for a design speed of 100 kmph when its ascending gradient is 2 %? Assuming coefficient of friction as 0.7 and brake efficiency as 50 %

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Solution

$S S D = 0.278 V t + \frac{V^{2}}{254 (k f + S %)}$
$= 0.278 \times 100 \times 2.5 + \frac{100^{2}}{254 (0.5 \times 0.7 + 0.02)}$
$= 175. 9 m$

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