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Question

What will be the normality of a solution obtained by diluting 200 mL of 0.6 N NaOH to 500 mL?

A
0.24 N
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B
b. 0.78 N
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C
0.34 N
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D
1.10 N
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Solution

The correct option is A 0.24 N
As per the law of dilution,
N1V1=N2V2
(0.60×200)=(N×500)
Normality of the final solution = 0.24 N

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