What will be the normality of a solution obtained by mixing $100 m L 0.1 N H C l$ and $200 m L 0.25 N H N O_{3}$ ?

0.2 N

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0.52 N

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0.50 N

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0.10 N

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Solution

The correct option is A $0.2 N$
Formula to calculate the normality of the solution after mixing is

$N_{1} V_{1} + N_{2} V_{2} = N_{3} V_{3}$

$N_{1} o f H C l = 0.1 N V_{1} o f H C l = 100 m L$
$N_{2} o f H N O_{3} = 0.25 N V_{2} o f H N O_{3} = 200 m L$

$N_{3}$ and $V_{3}$ are the normality & volume of the final solution.
$V_{3} = Total volume = 100 + 200 = 300 m L$
$(0.1 \times 100) + (0.25 \times 200) = N_{3} \times (300) 60 = N_{3} \times 300 N_{3} = 0.2 N$
The normality of the solution obtained is $0.2 N .$

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