Question

What will be the normality of a solution obtained by mixing $200ml$ of pure water to $100ml$ of 0.2N $HCl$ solution?

• A. $0.4N$
• B. $0.5N$
• C. $1.05N$
• D. $0.0667N$

Answer 1

The correct option is D $0.0667N$

This is a normality (N) times volume (V) problem and the equation we need is

$V_1\times N_1=V_2\times N_2$

where $V_1$ is the volume of the starting solution, $N_1$ the normality of the starting solution and $V_2/N_2$ the volume and normality of the ending solution. Here the question is asking for $N_2$ and

$N_2=V_1\times N_1/N_2=\frac{100\times 0.2}{100+200}=20/300=0.0667N$