Question

What will be the normality of the salt solution obtained by neutralizing x ml y (N) HCl with y ml x (N) NaOH, and finally adding (x + y) ml distilled water?

• A. $\frac{2(x+y)}{xy}N$
• B. $\frac{xy}{2(x+y)}N$
• C. $\left(\frac{2xy}{x+y}\right)N$
• D. $\left(\frac{x+y}{xy}\right)N$

Answer 1

Answer: (B)

$\frac{xy}{2(x+y)}N$

$HCl+NaOH\to NaCl+H_{2}O$
number of me added xy xy 0 0
number of me left 0 0 xy xy
Normality of salt solution $=\frac{\text{number of milliequivalent}}{\text{Volume of solution in mL}}=\frac{xy}{(x+y)+(x+y)}N=\frac{xy}{2(x+y)}N$