Question

What will be the number of aluminium ions in 0.051 g of aluminium oxide?

• A. $5.0\times {10}^{4}ions$
• B. $6.0\times {10}^{23}ions$
• C. $12\times {10}^{23}ions$
• D. $6.0\times {10}^{20}ions$

Answer 1

The correct option is D $6.0\times {10}^{20}ions$

No of mole of $Al=0.051\times 2/102$
and no of ions of Al $=0.051\times 2\times N_a/102=$ $6.0\times {10}^{20}ions$