Question

What will be the osmotic pressure of 0.1 M monobasic acid, its pH is 2 at ${25}^{\circ }$C?

Answer 1

$\left[H^{+}\right]=C\times alpha$
Therefore alpha $=\frac{0.01}{0.1}=0.1$
Now,
i=alpha +1
i=0.1+1
i=1.1
Osmotic pressure
=CRTi
=0.1RT1.1
=0.11RT