What will be the osmotic pressure of 0-2 M K 4- F e CN 6- solution at 27- C -A- 24-6 atmB- 49-2 atm- 4-92 atmD- 2 atm

The correct option is A 24.6 atmWe know, osmotic pressure (π), π = iCRT ⇒π= 5 × 0.2 × 0.0821 × 300 = 24.63 atm ...

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Standard XII

Chemistry

Half life

What will be ...

Question

What will be the osmotic pressure of 0.2 M $K_{4} [F e (C N)_{6}]$ solution at $27^{\circ} C$ ?

24.6 a t m

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49.2 a t m

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4.92 a t m

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2 a t m

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Solution

The correct option is A $24.6 a t m$
We know, osmotic pressure ( $π$ ),
$π = i C R T$
$\Rightarrow π = 5 \times 0.2 \times 0.0821 \times 300 = 24.63 a t m$

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What will be the osmotic pressure of 0.2 M K4[Fe(CN)6] solution at 27 ∘C ?

The correct option is A 24.6 atmWe know, osmotic pressure (π), π=iCRT ⇒π=5×0.2×0.0821×300=24.63 atm

What will be the osmotic pressure of 0.2 M $K_{4} [F e (C N)_{6}]$ solution at $27^{\circ} C$ ?

The correct option is A $24.6 a t m$
We know, osmotic pressure ( $π$ ),
$π = i C R T$
$\Rightarrow π = 5 \times 0.2 \times 0.0821 \times 300 = 24.63 a t m$