What will be the output of the following piece of code when executed-includevoidfint-iptr-iptr-1-mainint i-0-f i-cout-The value is-i-ends-return 0-

The correct option is A The value is 0The output of the following piece of #10;code when executed will be: #10;#include lt;iostream.h gt; #10;voidf(i ...

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Byju's Answer

Standard VII

Mathematics

Division of Integers

What will be ...

Question

What will be the output of the following piece of code when executed?
#include<iostream.h>
voidf(intiptr)
{
iptr=1;
}
main()
{
int i=0;
f(&i);
cout<<"The value is"<<i<<ends];
return 0;
}

The value is 0

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The value is 1

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will generate compiler error

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The value can not be specified i.e. it will contain garbage.

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Solution

The correct option is A The value is 0
The output of the following piece of code when executed will be:-
#include<iostream.h>
voidf(intiptr)
{
iptr=1;
}
main()
{
int i=0;
f(&i);
cout<<"The value is"<<i<<ends];
return 0;
}

Output:-

0.

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What will be the output of the following piece of code when executed?#include<iostream.h>voidf(int*iptr){*iptr=1;}main(){int i=0;f(&i);cout<<"The value is"<<i<<ends];return 0;}

The correct option is A The value is 0The output of the following piece of code when executed will be:- #include<iostream.h> voidf(int*iptr) { *iptr=1; } main() { int i=0; f(&i); cout<<"The value is"<<i<<ends]; return 0; } Output:- 0.

What will be the output of the following piece of code when executed?
#include<iostream.h>
voidf(intiptr)
{
iptr=1;
}
main()
{
int i=0;
f(&i);
cout<<"The value is"<<i<<ends];
return 0;
}

The correct option is A The value is 0
The output of the following piece of code when executed will be:-
#include<iostream.h>
voidf(intiptr)
{
iptr=1;
}
main()
{
int i=0;
f(&i);
cout<<"The value is"<<i<<ends];
return 0;
}

Output:-

0.