The correct option is A −13
Let the oxidation number of I is a inKI3.
⇒1+3×(a)=0
a=−13.
Alternative way,
KI3, is KI+I2
∴ I has two oxidation no. -1 and 0 respectively.
However factualy speaking oxidation number of I in KI3 is an average of two values - 1 and 0.
⇒ Average O.N.=−1+2×(0)3=−13.