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Question

What will be the oxidation number of "O" in O2F2 and ​ OF2 respectively ?

A
+1 and +12
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B
+2 and 1
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C
+2 and 12
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D
+1 and +2
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Solution

The correct option is D +1 and +2
O2F2 :
Since fluorine is more electronegative than oxygen so, oxidation state of fluorine is 1 in all its compounds. Let oxidation number of O atom in O2F2 is x.
2×x+1×(1)=0x=+1

1F+1O+1O1F
So, oxidation number of oxygen will be +1 as calculated.

OF2:
Let y be the oxidation state of "O" in OF2​.
Since the overall charge of a neutral molecule is zero. The sum of oxidation states of all elements in it should be equal to 0.
Therefore, y+2(1)=0y=+2

Hence, the oxidation state of "O "in OF2​ is +2.

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