wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

What will be the oxidation number of "O" in O2F2 and ​ OF2 respectively ?

A
+1 and +12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
+2 and 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
+2 and 12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
+1 and +2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D +1 and +2
O2F2 :
Since fluorine is more electronegative than oxygen so, oxidation state of fluorine is 1 in all its compounds. Let oxidation number of O atom in O2F2 is x.
2×x+1×(1)=0x=+1

1F+1O+1O1F
So, oxidation number of oxygen will be +1 as calculated.

OF2:
Let y be the oxidation state of "O" in OF2​.
Since the overall charge of a neutral molecule is zero. The sum of oxidation states of all elements in it should be equal to 0.
Therefore, y+2(1)=0y=+2

Hence, the oxidation state of "O "in OF2​ is +2.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon