What will be the oxidation number of underlined element
$C r - - O_{2} C l_{2}$

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-4

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Solution

The correct option is B 6
Let oxidation number of Cr be 'x' in $C r O_{2} C l_{2}$
$Oxidation number of C l = - 1$
$Oxidation number of O = - 2$
Let the Oxidation number of Cr is $x .$
$x + 2 \times (- 2) + 2 \times (- 1) = 0$
$x = + 6$

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