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Valency and Oxidation State

What will be ...

Question

What will be the oxidation state of Carbon in baking soda i.e. $N a H C O_{3}$

A

+ 2

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B

+ 3

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C

+ 4

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D

- 2

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Solution

The correct option is C $+ 4$
We know that bicarbonate exists as $H C O_{3}^{-}$ ion.
Charge on $N a = + 1$
Charge on $H = + 1$
Charge on $O = - 2$
Overall charge on $N a H C O_{3} = 0$
Let oxidation state of $C$ be $x$
$+ 1 + 1 + x + (3 \times (- 2)) = 0 x = + 4$
Theory :
Here are some important radicals with their formulas.
$Radicals Formula$
$Nitrate N O_{3}^{-}$
$Nitrite N O_{2}^{-}$
$Bisulphate H S O_{4}^{-}$
$Bicarbonate H C O_{3}^{-}$
$Cyanide C N^{-}$
$Sulphate S O_{4}^{2 -}$
$Sulphide S^{2 -}$
$Bromide B r^{-}$
$Chloride C l^{-}$
$Iodide I^{-}$
$Carbon monoxide C O$
$Nitric oxide N O$

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Valency and Oxidation State

Standard XII Chemistry

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