Question

What will be the oxidation state of Sulphur in $H_{2}S{O}_5$?

• A. $+8$
• B. $+6$
• C. $+4$
• D. $+2$

Answer 1

The correct option is B $+6$



As we can see in the above image that , there is a peroxy linkage i.e. $O-O$ linkage of 2 oxygen atoms, so the oxidation state of those 2 oxygen atoms will be $-1$.
Other 3 oxygen atoms have $-2$ oxidation state.
Overall charge $=0$
Let oxidation state of $S$ be $x$
So,
$(2\times +1)+x+(2\times -1)+(3\times -2)=0x=+6$
So, oxidation state of $S$ is $+6$