What will be the oxidation state of Sulphur in H2SO5?
A
+8
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B
+6
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C
+4
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D
+2
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Solution
The correct option is B+6
As we can see in the above image that , there is a peroxy linkage i.e. O−O linkage of 2 oxygen atoms, so the oxidation state of those 2 oxygen atoms will be −1. Other 3 oxygen atoms have −2 oxidation state. Overall charge =0 Let oxidation state of S be x So, (2×+1)+x+(2×−1)+(3×−2)=0x=+6 So, oxidation state of S is +6