What will be the pressure due to a water column of height $10 m$ . Take density of water $= 1000 k g$ $m^{- 3}$ , $g = 10 m$ $s^{- 2}$ . the answer is $p \times 10^{5} P a$ then p =

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Solution

Pressure at the bottom of the water collumn is given as,
$P = P o + ρ g h$
$P = 10^{5} P a + 1000 \times 10 \times 10$
$P = 2 \times 10^{5} P a .$

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What will be the pressure due to a water column of height 10m. Take density of water =1000kg m−3, g=10m s−2. the answer is p×105Pa then p =

Pressure at the bottom of the water collumn is given as, P=Po+ρgh P=105Pa+1000×10×10 P=2×105Pa.

What will be the pressure due to a water column of height $10 m$ . Take density of water $= 1000 k g$ $m^{- 3}$ , $g = 10 m$ $s^{- 2}$ . the answer is $p \times 10^{5} P a$ then p =

Pressure at the bottom of the water collumn is given as,
$P = P o + ρ g h$
$P = 10^{5} P a + 1000 \times 10 \times 10$
$P = 2 \times 10^{5} P a .$