You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Variation of Atmospheric Pressure with Altitude.

What will be ...

Question

What will be the pressure due to a water column of height $10 m$ . Take density of water $= 1000 k g$ $m^{- 3}$ , $g = 10 m$ $s^{- 2}$ . the answer is $p \times 10^{5} P a$ then p =

Open in App

Solution

Pressure at the bottom of the water collumn is given as,
$P = P o + ρ g h$
$P = 10^{5} P a + 1000 \times 10 \times 10$
$P = 2 \times 10^{5} P a .$

Suggest Corrections

Similar questions

Q. Calculate the pressure due to a water column of height 120 m. (Take

g = 10 m s^{- 2}

and density of water

= 103 k g m^{- 3}

)

Q. What is the pressure at a point

10 m

below the surface of a lake(see fig)?
Take

g = 10 m s^{- 2}; 1 a t m = 1.01 \times 10^{5} P a

;
Density of water

= 1000 k g / m^{3}

What will be the pressure in $d y n e$ ${c m}^{- 2}$ , due to a water column of height $12.5 c m$ ? ( $g = 980 c m$ $s^{- 2}$ ) (density of water $10^{3} k g$ $m^{- 3}$ ).

Q. Find the pressure at a depth of

0.6 m

in water of density

1000 k g

m^{- 3}

.(Take

g = 10 m

s^{- 1}

)

Q. If pressure at half depth of a lake is equal to

\frac{2}{3} r d

pressure at the bottom of the lake, then what is the depth of the lake?
(Take atmospheric pressure as

10^{5} Pa

, density of water as

1000 {kg/m}^{3}

and

g = 10 {m/s}^{2}

)

Join BYJU'S Learning Program

What will be the pressure due to a water column of height 10m. Take density of water =1000kg m−3, g=10m s−2. the answer is p×105Pa then p =

Pressure at the bottom of the water collumn is given as, P=Po+ρgh P=105Pa+1000×10×10 P=2×105Pa.

What will be the pressure due to a water column of height $10 m$ . Take density of water $= 1000 k g$ $m^{- 3}$ , $g = 10 m$ $s^{- 2}$ . the answer is $p \times 10^{5} P a$ then p =

Pressure at the bottom of the water collumn is given as,
$P = P o + ρ g h$
$P = 10^{5} P a + 1000 \times 10 \times 10$
$P = 2 \times 10^{5} P a .$