What will be the pressure of the gaseous mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1 L vessel at 27∘C?
1.8 bar
For H2, P1V1=P2V2⇒0.8× 0.5 =PH2× 1⇒ PH2= 0.4bar
For O2, P1V1=P2V2⇒0.7×2=PO2×1⇒ PO2= 1.4bar
Therefore, Ptotal=PH2+PO2 = 0.4 + 1.4 = 1.8