Question

What will be the pressure of the gaseous mixture when 0.5 L of $H_2$ at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1 L vessel at ${27}^{\circ }C$?

Answer 1

For $H_2$ gas

$P_1{V}_1=n_{1}RT$

$\Rightarrow 0.8\times 0.5=n_{H_2}\times 0.0821\times 300$

$\Rightarrow n_{H_2}=0.016$

For $O_2$ gas

$P_2{V}_2=n_{2}RT$

$\Rightarrow 0.7\times 2=n_{O_2}\times 0.0821\times 300$

$\Rightarrow n_{O_2}=0.056$

For Mixture

$PV=nRT$

$\Rightarrow P\times 1=\left(n_{H_2}+n_{O_2}\right)\times 0.0821\times 300$

$\Rightarrow P=\left(0.016+0.056\right)\times 0.0821\times 300$

$\Rightarrow$ $P=1.79bar$