What will be the product of following reaction
$O H |$ $O H |$
$C H_{3} - C - C - C H_{3} H_{2} S O_{4} - --- \to Q$
$| H$ $| H$

Q is ___________.

C H_{3} - C - C H_{2} - C H_{3}

| | O

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C H_{3} - C = C H - C H_{3}

| O H

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Both

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None

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Solution

The correct option is A $C H_{3} - C - C H_{2} - C H_{3}$
$| | O$

Dehydration reaction takes place with the hydride shift. The product is $2 - B u t a n o n e$ .

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Similar questions

300^{\circ} C

(a) C H_{3} - C H_{2} - O H | C H - C H_{3} (b) C H_{3} - 2 - O H | C | C H_{3} - C H_{3}

(c)_{╱ C H_{3}}^{C H_{3} ╲} C H - O H | C | C H_{3} - C H_{3} (d) C H_{3} - O H | C | C H_{3} - C H_{3}

O H^{-}, N H_{2}^{-}, H C \equiv C^{⊝}

C H_{3} - C H_{2}^{⊝}

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

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