Question

What will be the quotient and remainder if $(15y^4+10y^3-3y^2)÷5y^2$?

• A. Quotient = $(3y^2+2y-\frac{3}{5})$
  Remainder = $2y^2$
• B. Quotient = $(3y^2+2y-\frac{3}{5})$
  Remainder = $0$
• C. Quotient = $(3y^2+2y-\frac{3}{5})$
  Remainder = $2y^2+2$
• D. Remainder= $(3y^2+2y-\frac{3}{5})$
  Quotient= $2y^2$

Answer 1

The correct option is B Quotient = $(3y^2+2y-\frac{3}{5})$

Remainder = $0$
Given: $(15y^4+10y^3-3y^2)=\left(5y^2\right)$

$$\begin{array}{c}3y^2+2y-\frac{3}{5}\\ 5y^{2}15y^4+10y^3-3y^2\\ \underset{–}{15y^4(-)}2\\ 10y^3-3y^2\\ \underset{–}{10y^3(-)}\\ -3y^2\\ \underset{–}{-3y^2}\\ \underset{–}{0}\end{array}$$

Quotient = $(3y^2+2y-\frac{3}{5})$
Remainder = 0