Question

What will be the quotient and remainder if $(2x^3+4x^2-5)÷(x+3)$? (3 marks)

Answer 1

Given: $(2x^3+4x^2-5)÷(x+3)$
$\begin{array}{c}2x^2-2x+6\\ x+32x^3+4x^2-5\\ \underset{–}{2x^3+6x^2--}2\\ -2x^2-5\\ \underset{–}{-2x^2-6x++}\\ 6x-5\\ \underset{–}{6x+18--}\\ \underset{–}{-23}\end{array}$
(2 marks)

Quotient = $(2x^2-2x+6)$
Remainder = $(-23)$ (1 mark)