Question

What will be the quotient and remainder if $(p^2+7p-5)÷(p+3)$?

• A. Quotient = $(p^2+4p)$
  Remainder = $(-7)$
• B. Quotient = $(p+4)$
  Remainder = $(-71)$
• C. Quotient = $(p+4)$
  Remainder = $(-17+2p)$
• D. Quotient = $(p+4)$
  Remainder = $(-17)$

Answer 1

The correct option is D Quotient = $(p+4)$

Remainder = $(-17)$
Given: $(p^2+7p-5)÷(p+3)$
$\begin{array}{c}p+4\\ p+3p^2+7p-5\\ \underset{–}{p^2+3p--}2\\ 4p-5\\ \underset{–}{4p+12--}\\ \underset{–}{-17}\end{array}$
Quotient = $(p+4)$
Remainder = $(-17)$