Question

What will be the radius of the FCC lattice if it has the edge length of $534$ pm?

• A. $188.8pm$
• B. $128.8pm$
• C. $238.8pm$
• D. $168.8pm$

Answer 1

The correct option is A $188.8pm$

For a face-centered cubic lattice,

$radius=\frac{edge\times \sqrt{2}}{4}$

$\therefore r=\frac{a}{2\sqrt{2}}$

$=\frac{534}{2\times \sqrt{2}}$

$=188.8pm$

Hence, option $\left(A\right)$ is correct.