Question

What will be the rate of the simple reaction $2NO+O_2\to 2N{O}_2$, when the volume of the reaction vessel is doubled?

• A. Will grow eight times of its initial rate
• B. Rate reduce to one eights of its initial rate
• C. Will grow four times of its initial rate
• D. Reduce to one fourth of its initial rate

Answer 1

The correct option is B Rate reduce to one eights of its initial rate

In the simple reaction, $2NO+O_2\to 2N{O}_2$

Rate $=K\left[NO{]}^2\right[O_2]$ ----- 1

If the volume of the vessel is doubled, the concentration of reactant became half.

New rate $=K\left[\frac{NO}{2}{]}^2\right[\frac{O_2}{2}]=\frac{1}{8}K[NO{]}^2\left[O_2\right]$ ---- 2

So, the new rate reduces one-eighth of the initial rate.