What will be the ratio of $C l^{35}$ and $C l^{37}$ respectively in chlorine if the average atomic mass of chlorine is 35.5?

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 : 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3 : 1
Let percentage abundance of $C l_{37} = x$

Percentage abundance of $C l_{35.5} = 1 - x$

Average atomic mass $= Σ (m a s s_{(i)}) (a b u n d a n c e_{(i)})$

$37 x + 35 (1 - x) = 35.5$

$37 x + 35 - 35 x = 35.5$

$2 x = 0.5$

$x = 0.25$

Hence, 25% $C l_{37}$ and 75% $C l_{35}$ .

So, the ratio of $C l_{35}$ and $C l_{37}$ is $3 : 1$ .

Hence, option C is correct.

Suggest Corrections

Similar questions

Q. What will be the ratio of

C l^{35}

and

C l^{37}

respectively in ordinary chlorine if the atomic weight of chlorine is 35.5 ?

Q. In chlorine gas, ratio of

C l^{35}

and

C l^{37}

is?

Naturally occurring chlorine consists of two isotopes whose atomic weights are 35 and 37. The atomic weight of natural chlorine is 35.5, then what is the ratio of $C l^{35} t o C l^{37}$ ?

^{35} C l

and

^{37} C l

are the two isotopes of chlorine, in the ratio

3 : 1

respectively. If the isotope ratio is reversed the average atomic mass of chlorine will be:

Join BYJU'S Learning Program

What will be the ratio of Cl35 and Cl37 respectively in chlorine if the average atomic mass of chlorine is 35.5?

The correct option is B 3 : 1Let percentage abundance of Cl37=xPercentage abundance of Cl35.5=1−xAverage atomic mass =Σ(mass(i))(abundance(i))37x+35(1−x)=35.537x+35−35x=35.52x=0.5x=0.25Hence, 25% Cl37 and 75% Cl35.So, the ratio of Cl35 and Cl37 is 3:1.Hence, option C is correct.

What will be the ratio of $C l^{35}$ and $C l^{37}$ respectively in chlorine if the average atomic mass of chlorine is 35.5?