What will be the ratio of $C l^{35}$ and $C l^{37}$ respectively in ordinary chlorine if the atomic weight of chlorine is 35.5 ?

1:3

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3:1

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1:2

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2:1

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Solution

The correct option is C 3:1
Using average molcular mass formula:

$x (35) + (1 - x) (37) = 35.5$

$x = 0.75$

$1 - x = 0.25$

$\frac{0.75}{0.25} = 3 : 1$

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Similar questions

Q. What will be the ratio of

C l^{35}

and

C l^{37}

respectively in chlorine if the average atomic mass of chlorine is 35.5?

Naturally occurring chlorine consists of two isotopes whose atomic weights are 35 and 37. The atomic weight of natural chlorine is 35.5, then what is the ratio of $C l^{35} t o C l^{37}$ ?

Q. In chlorine gas, ratio of

C l^{35}

and

C l^{37}

is?

^{35} C l

and

^{37} C l

are the two isotopes of chlorine, in the ratio

3 : 1

respectively. If the isotope ratio is reversed the average atomic mass of chlorine will be:

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What will be the ratio of Cl35 and Cl37 respectively in ordinary chlorine if the atomic weight of chlorine is 35.5 ?

The correct option is C 3:1Using average molcular mass formula:x(35)+(1−x)(37)=35.5 x=0.75 1−x=0.25 0.750.25=3:1

What will be the ratio of $C l^{35}$ and $C l^{37}$ respectively in ordinary chlorine if the atomic weight of chlorine is 35.5 ?

The correct option is C 3:1
Using average molcular mass formula:

$x (35) + (1 - x) (37) = 35.5$

$x = 0.75$

$1 - x = 0.25$

$\frac{0.75}{0.25} = 3 : 1$