What will be the ratio of corresponding sides formed in the construction of a similar triangle to ΔABC, if C divides the line segment AB in the ratio 8:17?

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Solution

The ratio of corresponding sides will be AC:AB.

$\frac{A C}{B C}$ = $\frac{8}{17}$ .

Therefore,

$\frac{B C}{A C}$ = $\frac{17}{8}$

$\frac{A B}{A C}$ = 1+ $\frac{B C}{A C}$

So, the ratio of corresponding sides will be 8:25.

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