What will be the ratio of the masses of equal volumes of ammonia and hydrogen sulphide under the same conditions of temperature and pressure?

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Solution

At same temperature and pressure, equal volume of $N H_{3}$ and $H_{2} S$ have equal moles.
$n_{{N H}_{3}} = n_{H_{2} S} ⟹ \frac{m_{{N H}_{3}}}{17} = \frac{m_{H_{2} S}}{34} ⟹ m_{{N H}_{3}} : m_{H_{2} S} = 1 : 2$

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What will be the ratio of the masses of equal volumes of ammonia and hydrogen sulphide under the same conditions of temperature and pressure?

At same temperature and pressure, equal volume of NH3 and H2S have equal moles.nNH3=nH2S⟹mNH317=mH2S34⟹mNH3:mH2S=1:2

At same temperature and pressure, equal volume of $N H_{3}$ and $H_{2} S$ have equal moles.
$n_{{N H}_{3}} = n_{H_{2} S} ⟹ \frac{m_{{N H}_{3}}}{17} = \frac{m_{H_{2} S}}{34} ⟹ m_{{N H}_{3}} : m_{H_{2} S} = 1 : 2$