What will be the recombination frequency between two gene (a and b), if the linkage map of X-chromosomes of Drosophila has 66 units, with yellow body gene (a) at one end and bobbed hair gene (b) at another end? (a)

\leq 50

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Exact 66%

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> 50

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Exact 100%

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Solution

The correct option is D Exact 100%
The actual distance between two genes is said to be equivalent to the percentage of crossing over between these two genes. Since the two gene of X- chromosome of Drosophila and yellow body gene lie at the ends of the chromosome so there are 100% chances of their segregation during crossing over.
Hence answer is option D.

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