What will be the resultant pH when 150 mL of an aqueous solution of HCl(pH=2.0) is mixed with 350 mL of an aqueous solution of NaOH(pH=12.0)?
Take log(2)=0.3
A
8.6
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B
12.6
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C
11.6
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D
10.6
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Solution
The correct option is C 11.6 pHofHCl=2 ∴[H]+=10−2M pHofNaOH=12,pOH=2∴[OH]−=10−2M