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Question

What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH=2.0) is mixed with 350 mL of an aqueous solution of NaOH ( pH=12.0)?
Take log(2)=0.3

A
8.6
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B
12.6
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C
11.6
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D
10.6
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Solution

The correct option is C 11.6
pH of HCl=2
[H]+=102 M
pH of NaOH=12, pOH=2 [OH]=102 M

HCl+NaOHNaCl+H2Omeq. initial150×102350×10200meq. final021.51.5

[OH] from NaOH=2500=4×103M
pOH=log[OH]=log(4×103)
pOH=((2×0.3)3)=2.4
pH=14pOH=142.4=11.6

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