What will be the root mean square velocity of gas molecules at 0 $^{o}$ C if at N.T.P its density is 1.43 Kg/m $^{3}$ ?

461 m / s

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164 m / s

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461 c m / s

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164 c m / s

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Solution

The correct option is A $461 m / s$
$C_{r m s} = \sqrt{\frac{3 P}{d}} C_{r m s} = \sqrt{\frac{3 \times {1.01 \times 10}^{5}}{1.43}} C_{r m s} = 461 m / s$

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What will be the root mean square velocity of gas molecules at 0oC if at N.T.P its density is 1.43 Kg/m3 ?

The correct option is A 461 m/sCrms=√3PdCrms=√3×1.01×1051.43Crms=461m/s

What will be the root mean square velocity of gas molecules at 0 $^{o}$ C if at N.T.P its density is 1.43 Kg/m $^{3}$ ?

The correct option is A $461 m / s$
$C_{r m s} = \sqrt{\frac{3 P}{d}} C_{r m s} = \sqrt{\frac{3 \times {1.01 \times 10}^{5}}{1.43}} C_{r m s} = 461 m / s$