Question

What will be the self inductane of a coil of $100$ turns if a current of $5A$ produces a magnetic flux $5\times {10}^{-5}$ Wb?

• A. $1mH$
• B. $10mH$
• C. $1\mu H$
• D. $10\mu H$

Answer 1

The correct option is A $1mH$

GIven : $N=100$ turns $I=5$ $A$ $\varphi =5\times {10}^{-5}$ $Wb$

Using ${\varphi }_T=LI$ where $L$ is the self inductance

$\therefore$ $n\times \varphi =LI$

$100\times 5\times {10}^{-5}=L\times 5$ $⟹L={10}^{-3}H=1mH$