Question

What will be the shape of $I_3^{+}$ among the following ?

• A. Tetrahedral
• B. Bent
• C. Linear
• D. Trigonal planar

Answer 1

The correct option is B Bent

$I_3^{+}$ has 2 bond pair and 2 lone pair so steric number is 4 and hybridisation will be $s{p}^3$. Hence it has tetrahedral geometry and bent shape due to two pairs.


We can also find steric number using:
s = (m+v-q) / 2
where s = steric number
m = number of monovalent surrounding atoms
v = valence electrons on central atom
q = charge with sign

so, we have m =2 , v = 7, q = +1 putting in formula we get s = (2+7-1)/2 = 4, so $s{p}^3$ hybridisation.