What will be the shape of I+3 among the following ?
A
Tetrahedral
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B
Bent
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C
Linear
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D
Trigonal planar
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Solution
The correct option is B Bent I+3 has 2 bond pair and 2 lone pair so steric number is 4 and hybridisation will be sp3. Hence it has tetrahedral geometry and bent shape due to two pairs.
We can also find steric number using: s = (m+v-q) / 2 where s = steric number m = number of monovalent surrounding atoms v = valence electrons on central atom q = charge with sign
so, we have m =2 , v = 7, q = +1 putting in formula we get s = (2+7-1)/2 = 4, so sp3 hybridisation.