What will be the simplest formula of the comopund if in a crystalline solid, atoms of X form fcc packing and the atoms of Y occupy all the octahedral voids?
A
XY
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B
XY2
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C
X4Y
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D
XY4
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Solution
The correct option is AXY In fcc packing (at corners and face centres of cubic unit cell) Number of atoms of X=8×18+6×12=4
No of octahedral voids = Number of atoms in FCC = 4 Number of atoms of Y=4
Formula: X4Y4
Simplest formula: XY