What will be the sum of roots taken two at a time in the equation $2 x^{3} - 7 x^{2} - 9 x + 7 = 0$ ?

\frac{9}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 7}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{- 9}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{- 9}{2}$
Sum of roots taken two at a time in a cubic equation $a x^{3} + b x^{2} + c x + d = 0$ is given by: $\frac{c}{a}$ , so here $\frac{- 9}{2}$

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ \begin{matrix} x & 3 & 7 2 & x & 2 7 & 6 & x \end{matrix} ∣ ∣ ∣ ∣

4 x^{7} + 3 x^{6} + 2 x^{5} + 9 x^{4} + 4 x^{3} + x^{2} + 9 x + 9 = 0

x^{2} - 2 (1 + 3 m) x + 7 (3 + 2 m) = 0

m = 2, - \frac{10}{9} .

^{'} 0^{'}

^{'} 1^{'} .

- 9

∣ ∣ ∣ ∣ \begin{matrix} x & 3 & 7 2 & x & 2 7 & 6 & x \end{matrix} ∣ ∣ ∣ ∣ = 0

∣ ∣ ∣ ∣ \begin{matrix} x & 3 & 7 2 & x & 2 7 & 6 & x \end{matrix} ∣ ∣ ∣ ∣

Join BYJU'S Learning Program