What will be the tens place digit in the following expression:
1! + 2! + 3! + ... + 70!?

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1
There are numbers for tens place digit, divide the expression by 100; however, we know that 10! and greater than 10! is divisible by 100 because there are at least two 5s in these numbers.
Now, divide 1! + 2! + 3! ... + 9! by 100 and find the remainder.

Suggest Corrections

Similar questions

(1!) + (2!)^{2} + (3!)^{3} + (4!)^{4} + (5!)^{5} + \dots (111!)^{111}

Find the digit in the tens place in a number which is expressed as 700 + 60 + 3.

Join BYJU'S Learning Program