What will be the transfer of momentum when a dumb bell of mass 15 kg falls from a height of 50cm and does not rebound? ( Take its downward acceleration to be 10 ms-2)
58 Ns
Step 1: Calculate the final velocity of the dumb-bell
Mass of dumb–bell (m) = 15 kg
Initial velocity (u) = 0
Final velocity (v) = ?
Distance (S) = 50 cm = 0.5m
Acceleration (a) = 10 ms–2
We know v2 – u2 = 2aS
v2 – (0)2 = 2 × 15 × 0.5
v2 = 15
v = 3.87 ms–1
Momentum of dumb-bell transferred to ground = mv = 15 × 3.87 = 58 Ns.