We know that if a standard parabola is shifted by h units along positive x-axis then the equation of translated parabola is given by (x−h)2=4ay.
So, according to question the equation of translated parabola shifted by 6 units along x-axis is given by (x−6)2=4y.
Also, upon opening the square we get the equation as
x2−12x+36=4y
⇒x2+36=4y+12x.
Hence, A and C are correct answer.