Question

What will be the value of ${\Delta G}^O$. If equilibrium constant for a reaction is $10$?

• A. $-50.44KJ{mol}^{-1}$
• B. $-5.705KJ{mol}^{-1}$
• C. $-25.44KJ{mol}^{-1}$
• D. $-10KJ{mol}^{-1}$

Answer 1

The correct option is B $-5.705KJ{mol}^{-1}$

$K=10$, $T=298$ $K$

$\Delta G^o=-2.303RT\log K$

$⟹\Delta G^o=-2.303\times 8.314\times 298$

$⟹\Delta G^o=-5.705$ $kJ$ $mo{l}^{-1}$