Question

What will be the value of m and $c$ if the straight line $y=mx+c$ passes through the points $(3,-4)$ and $(-1,2)$?

Answer 1

by the equation of the straight line passing through two points is

$(y-y_1)=\frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)$
Here the points are

$(3,-4),(-1,2)$

Then,

$(y-(-4\left)\right)/(2-(-4\left)\right)=(x-3)/(-1-3)$

$(y+4)/6=(x-3)/-4$

-4(y+4) = 6(x-3)

-4y-16 = 6x-18

-4y=6x-2

y=-(3/2)x+(1/2)

Therefor by comparing this with $y=mx+c$ we get,

m = -(3/2)

c = (1/2)