What will be the value of pH of $0.01 m o l d m^{- 3} C H_{3} C O O H (K_{a} = 1.74 \times 10^{- 5})$ ?

3.4

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3.6

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3.9

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3.0

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Solution

The correct option is A $3.4$
$C H_{3} C O O H C (1 - α) + H_{2} O ⟶ H_{3} O C α + C H_{3} C O O C α$
$K_{a} = C α^{2} \Rightarrow α = \sqrt{\frac{K a}{C}}$
$[H_{3} O^{+}] = \sqrt[C]{\frac{K a}{c}} = \sqrt{K a . C}$
$= \sqrt{0.01 \times 1.74 \times 10^{- 5}}$
$\sqrt{1.74 \times 10^{- 7}} = 4, 17 \times 10^{- 4}$
$P H_{2} - log (4.17 \times 10^{- 4}) = 3.38 ≃ 3.4$

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Question 9
A company manufactures car batteries of a particular type. The lives (in years) of 40 such batteries were recorded as follows:
$\begin{matrix} 2.6 & 3.0 & 3.7 & 3.2 & 2.2 & 4.1 & 3.5 & 4.5 3.5 & 2.3 & 3.2 & 3.4 & 3.8 & 3.2 & 4.6 & 3.7 2.5 & 4.4 & 3.4 & 3.3 & 2.9 & 3.0 & 4.3 & 2.8 3.5 & 3.2 & 3.9 & 3.2 & 3.2 & 3.1 & 3.7 & 3.4 4.6 & 3.8 & 3.2 & 2.6 & 3.5 & 4.2 & 2.9 & 3.6 \end{matrix}$
Construct a grouped frequency distribution table for this data, using class intervals of size 0.5 starting from the intervals 2−2.5.