What will be the value of van't Hoff fator for $K_{3} [F e (C N)_{6}]$ , if it undergoes $75 %$ dissociation in aqueous medium?

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Solution

$K_{3} [F e (C N)_{6}]$ will dissociate as,
$\begin{matrix} K_{3} [F e (C N)_{6}] \to & 3 K^{+} + & [F e (C N)_{6}]^{3 -} C & 0 & 0 C - C α & 3 C α & C α \end{matrix}$
Therefore, van't Hoff fator, $(i) = \frac{C - C α + 3 C α + C α}{C} = 1 + 3 α$
Here, given, $α = 0.75$
$∴ i = 1 + 3 \times 0.75 = 3.25$

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