What will be the value of x1-2- x1-4- x1-8- to infinity-

The correct option is D x The expression can be written as x^(1/2 + 1/4 + 1/8 + 1/16)..... = x^(infinite sum of the GP) = x^1 ...

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What will be the value of $x^{\frac{1}{2}} . x^{\frac{1}{4}} . x^{\frac{1}{8}} . . .$ to infinity.

$x^{2}$

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$x$

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$x^{\frac{3}{2}}$

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$x^{3}$

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x^{\frac{1}{2}} . x^{\frac{1}{4}} . x^{\frac{1}{8}} . x^{\frac{1}{16}} . . . . .

\infty

\frac{x - 1}{x^{3 / 4} + x^{1 / 2}} \times \frac{x^{1 / 2} + x^{1 / 4}}{x^{1 / 2} + 1} \times x^{1 / 4}

x^{1 / 2} \cdot x^{1 / 4} \cdot x^{1 / 8} \dots \infty

The infinite product $x^{\frac{1}{2}} . x^{\frac{1}{4}} . x^{\frac{1}{8}} . . . . . . . . . . .$ equals ___.

x : \frac{1}{8} = \frac{1}{5} : \frac{1}{2}

x

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